(C) The light from the point source will emerge from the top surface only if the angle of incidence at the top surface is less than or equal to the cr

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(C) The light from the point source will emerge from the top surface only if the angle of incidence at the top surface is less than or equal to the critical angle $C$.The radius $R$ of the circular area is given by the formula $R = \frac{h}{\sqrt{\mu^2 - 1}}$,where $h$ is the thickness of the slab and $\mu$ is the refractive index.Given: $h = 8 \, cm$ and $\mu = \frac{5}{3}$.Substituting the values:$R = \frac{8}{\sqrt{(\frac{5}{3})^2 - 1}}$$R = \frac{8}{\sqrt{\frac{25}{9} - 1}}$$R = \frac{8}{\sqrt{\frac{16}{9}}}$$R = \frac{8}{4/3} = \frac{8 \times 3}{4} = 6 \, cm$.

Class 12 Physics Ray Optics and Optical Instruments Refraction through Plane Surface and Glass Slab

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$A$ large glass slab $\left( \mu = \frac{5}{3} \right)$ of thickness $8 \, cm$ is placed over a point source of light on a plane surface. It is seen that light emerges out of the top surface of the slab from a circular area of radius $R \, cm$. What is the value of $R$? ....... $cm$

A
$2$
B
$3$
C
$6$
D
$5$

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Ray Optics and Optical Instruments

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Refraction through Plane Surface and Glass Slab

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$A$ large glass slab $\left( \mu = \frac{5}{3} \right)$ of thickness $8 \, cm$ is placed over a point source of light on a plane surface. It is seen that light emerges out of the top surface of the slab from a circular area of radius $R \, cm$. What is the value of $R$? ....... $cm$

Similar Questions

$A$ light wave is incident normally on a glass slab of refractive index $1.5$. If $4\%$ of light gets reflected and the amplitude of the electric field of the incident light is $30\, V/m$,then the amplitude of the electric field for the wave propagating in the glass medium will be.......$ V/m$

$A$ glass slab of thickness $3 \ cm$ is placed on an ink mark on a piece of paper. For a person looking at the mark from a distance of $5.0 \ cm$ above the top surface of the slab, the mark appears to be at a distance of $4.0 \ cm$ from the observer. The refractive index of the slab is:

$A$ fish at a depth of $12 \, cm$ in water is viewed by an observer on the bank of a lake. To what height is the image of the fish raised? (Refractive index of water $\mu = 4/3$)

$A$ paraxial beam of light is converging towards a point $P$ on the screen. $A$ plane parallel sheet of glass of thickness $t$ and refractive index $\mu$ is introduced in the path of the beam. The convergence point is shifted by:

Three immiscible liquids of densities $d_1 > d_2 > d_3$ and refractive indices $\mu_1 > \mu_2 > \mu_3$ are put in a beaker. The height of each liquid column is $\frac{h}{3}$. $A$ dot is made at the bottom of the beaker. For near normal vision,find the apparent depth of the dot.

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